Home
Math symbols
Jokes
Forum
About us
Links
Contact us
Site map
Search The Site
   
   Program of Lessons
 
 Study Guide
 Topics of problems
 Tests & exams
 Tuition Payment
www.bymath.com Study Guide - Arithmetic Study Guide - Algebra Study Guide - Geometry Study Guide - Trigonometry Study Guide - Functions & Graphs Study Guide - Principles of Analysis Study Guide - Sets Study Guide - Probability Study Guide - Analytic Geometry Select topic of problems Select test & exam Rules Price-list Registration

                                                               

Plane

 

General equation of plane. Normal vector.

Equation of plane in segments on axes.

Equation of plane going through the given point

and perpendicular to the given vector.

Parallelism condition of planes.

Perpendicularity condition of planes.

Distance between two points.

Distance from point to plane.

Angle between planes.

 

A general equation of plane:

 

Àõ +  Âó +  Ñz +  D = 0 ,

 

where  À, B and C  aren't equal to zero simultaneously.

Coefficients À, B and C are coordinates of normal vector of  the plane ( i.e. vector, perpendicular to the plane ).

 

At  À 0,  Â 0,  Ñ 0 and D 0  we receive an equation of plane in segments on axes:

 

where  a = – D / A,  b = – D / B,  c = – D / C. This plane goes through the points ( a, 0, 0 ), ( 0, b, 0 ) and ( 0, 0, ñ ), i.e. it cuts off segments  a, b and  c  long on the coordinate axes.

 

An equation of plane, going through a point  ( õ0 ,  ó 0 ,  z 0 )  and perpendicular to a vector ( À, Â, C ) :

 

À ( õ õ0 ) + Â ( ó ó 0 ) + Ñ ( z z 0 ) = 0 .

 

A parallelism condition of planes  Àõ+ Âó+ Ñz+ D = 0  and  Eõ+ Fó+ Gz+ H = 0 :

 

AFBE = BGCF = AGCE = 0 .

 

A perpendicularity condition of planes Àõ+ Âó+ Ñz+ D = 0 and Eõ+ Fó+ Gz+ H = 0 :

 

ÀE+ ÂF+ ÑG = 0 .

A distance between two points ( x1 ,  y 1 ,  z1 ) and ( x2 ,  y2 ,  z2) :

A distance from a point  ( õ0 ,  ó 0 ,  z 0 )   to a plane  Àõ + Âó + Ñz + D = 0 :

An angle    between planes  Àõ+ Âó+ Ñz+ D = 0  and  Eõ+ Fó+ Gz+ H = 0 :

 

Back


| Home | About us | Links | Contact us |

Copyright © 2002-2007 Dr. Yury Berengard.  All rights reserved.