Home
Math symbols
Jokes
Forum
About us
Links
Contact us
Site map
Search The Site
   
   Program of Lessons
 
 Study Guide
 Topics of problems
 Tests & exams
www.bymath.com Study Guide - Arithmetic Study Guide - Algebra Study Guide - Geometry Study Guide - Trigonometry Study Guide - Functions & Graphs Study Guide - Principles of Analysis Study Guide - Sets Study Guide - Probability Study Guide - Analytic Geometry Select topic of problems Select test & exam Rules Price-list Registration

Division of polynomials


Division of polynomials (quotient, remainder). Long division.

Division of polynomials. What means to divide one polynomial  by another Q ? It means to find polynomials M  ( quotient ) and N  ( remainder ), satisfying the two requirements:

          1).  An equality  MQ + N = P   takes place;
          2).  A degree of polynomial  N  is less than a degree of polynomial Q

Division of polynomials can be done by the following scheme ( long division ):

1)  Divide the first term 16a3 of the dividend by the first term  4a2 of the divisor;  the result  4a  is the first term of the quotient.

2)  Multiply the received term 4a  by the divisor 4a2 – a + 2; write the result 16a3 4a2 + 8a  under the dividend, one similar term under another.

3)  Subtract terms of the result from the corresponding terms of the dividend and move down the next by the order term 7 of the dividend; the remainder is 12a2 13a + 7 .

4)  Divide the first term 12a2 of this expression by the first term 4a2 of the divisor;  the result 3 is the second term of the quotient.

5)  Multiply the received second term 3 by the divisor 4a2 – a + 2; write the result 12a23a + 6 again under the dividend, one similar term under another.

6)  Subtract terms of the result from the corresponding terms of the previous remainder and receive the second remainder:
     – 10a + 1. Its degree is less than the divisor degree,  therefore the division has been finished. The quotient is  4a + 3,
     the remainder is 
10a + 1.

Back


| Home | About us | Links | Contact us |

Copyright © 2002-2007 Dr. Yury Berengard.  All rights reserved.